B^2=12+4b

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Solution for B^2=12+4b equation: 



^2=12+4B

We move all terms to the left:

^2-(12+4B)=0

We add all the numbers together, and all the variables

-(4B+12)+^2=0

We add all the numbers together, and all the variables

-(4B+12)=0

We get rid of parentheses

-4B-12=0

We move all terms containing B to the left, all other terms to the right

-4B=12

B=12/-4

B=-3

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